2[6x-4(x-2)]=7x+1

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Solution for 2[6x-4(x-2)]=7x+1 equation:


Simplifying
2[6x + -4(x + -2)] = 7x + 1

Reorder the terms:
2[6x + -4(-2 + x)] = 7x + 1
2[6x + (-2 * -4 + x * -4)] = 7x + 1
2[6x + (8 + -4x)] = 7x + 1

Reorder the terms:
2[8 + 6x + -4x] = 7x + 1

Combine like terms: 6x + -4x = 2x
2[8 + 2x] = 7x + 1
[8 * 2 + 2x * 2] = 7x + 1
[16 + 4x] = 7x + 1

Reorder the terms:
16 + 4x = 1 + 7x

Solving
16 + 4x = 1 + 7x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-7x' to each side of the equation.
16 + 4x + -7x = 1 + 7x + -7x

Combine like terms: 4x + -7x = -3x
16 + -3x = 1 + 7x + -7x

Combine like terms: 7x + -7x = 0
16 + -3x = 1 + 0
16 + -3x = 1

Add '-16' to each side of the equation.
16 + -16 + -3x = 1 + -16

Combine like terms: 16 + -16 = 0
0 + -3x = 1 + -16
-3x = 1 + -16

Combine like terms: 1 + -16 = -15
-3x = -15

Divide each side by '-3'.
x = 5

Simplifying
x = 5

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